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Openai/6897769e-4ee4-800f-aba5-69cca34f701c
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==== I also solved for the required Ξ΄ that makes the formula produce the observed GGG for each Ξ½: ==== Ξ΄reqβ β=β βGobsβββΞ½4Οc3r0.\delta_{\rm req} \;=\; \frac{G_{\rm obs}\,\hbar\,\nu}{4\pi c^3 r_0}.Ξ΄reqβ=4Οc3r0βGobsββΞ½β. With r0=a0r_0=a_0r0β=a0β: * Ξ½ = light-crossing β Ξ΄_req β 3.5Γ10β433.5\times10^{-43}3.5Γ10β43 m * Ξ½ = 1e8 β Ξ΄_req β 3.9Γ10β533.9\times10^{-53}3.9Γ10β53 m * Ξ½ = 1e12 β Ξ΄_req β 3.9Γ10β493.9\times10^{-49}3.9Γ10β49 m * Ξ½ = 1e15 β Ξ΄_req β 3.9Γ10β463.9\times10^{-46}3.9Γ10β46 m These required thicknesses are tiny β far smaller than the Planck length (βPβ1.62Γ10β35\ell_P\approx1.62\times10^{-35}βPββ1.62Γ10β35 m). Physically impossible in known physics. That means: for an atomic shell radius, you cannot get the right GGG with any plausible Ξ΄ or Ξ½ that is not already Planckian or smaller.
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