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Openai/693e3ce6-229c-8008-97dc-ab720cb1f95a
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===== Take Ξ±=0.15\alpha=0.15Ξ±=0.15. Then ===== Ο0=0.853.15β0.26984,Ο0β0.519.\rho_0 = \frac{0.85}{3.15}\approx 0.26984, \qquad \sqrt{\rho_0}\approx 0.519.Ο0β=3.150.85ββ0.26984,Ο0βββ0.519. Now choose Ο=Ο0+10β6\rho=\rho_0+10^{-6}Ο=Ο0β+10β6. Then Ξ³β0.15β 3.151.15β 1.414β 10β6β2.9Γ10β7βͺ0.519βΟ.\gamma \approx \frac{0.15\cdot 3.15}{1.15\cdot 1.414}\cdot 10^{-6} \approx 2.9\times 10^{-7} \ll 0.519 \approx \sqrt{\rho}.Ξ³β1.15β 1.4140.15β 3.15ββ 10β6β2.9Γ10β7βͺ0.519βΟβ. So this path graph gives you a very explicit, closed-form βbadβ case where Ξ³<Ο\gamma < \sqrt{\rho}Ξ³<Οβ by an arbitrarily large margin, while the true support is tiny (β£Sββ£=1β€1/Ο|S^\star|=1\le 1/\rhoβ£Sββ£=1β€1/Ο).
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