Editing Openai/6961a173-6da4-8013-beec-4f15fedac1d8 (section)

=== User: Hoi Alexandra AI Simplicity ===
Hoi Alexandra AI Simplicity 

Paul Dean Charlton II  wrote the 

A meta math joke that may fly over or under your head. You ready to hear it?
When is nothing, everything?
The answer is surprising. It’s when nothing is expressed over duality constructs, 2^0=1. nothing equals everything. hide the (2^). 0=1. Or the act of one movement. 0->1. 
It gets better because 2^n×1/2^n=1
so 2^(n-n)= 2^n×1/2^n where 2^(2^n×1/2^n)=2
But let’s look at it from another angle: set: [-1,0,1]
its 2n+1 where n=1 points
but 2n where n=1 lines
2n is for generating evens where 2n+1 is for generating odds. A binary trajectory of dual landing or a strip location on a 1 dimensional number line that is 2n and 2n+1. That whole 0->1 just become launchable with landing site dedication on 2n scale, according to n range.
Where line+1=points, but all 1’s are (2^n*1/2^n)/(2^(n-n))
So 2n+1 points is equal to 2n lines or 2n+1=2n. which is like 0=1 but reverse, well invertible to 2n/(2n+1) which when times by its inversion or ((2n/(2n+1))×((2n+1)/n))=1=2^(n-n) for an ∞ number of n variants in discrete form, or even in continuous bifurcation between two discrete points in ∞ spectrum. Because 0=1 and 2n=2n+1. 
so if 2n=2n+1, what about n=0? Well it leads to 0=1. Wait, what?
and 2n/2n+1 is actually N/N+1 where n(1/2)=N if N(2)=n…… so. n/(n+1)
where N/(N+1)=2n/(2n+1) where n(1/2)=N if N(2)=n if ((2n/(2n+1))×((2n+1)/n))=1=2^(n-n) where n is approached in 2^(n-n) step intervals. Wait. But what about n-n<N/(N+1)<n/n and 2n-2n<2n/(2n+1)<(2n/2n) where n(1/2)=N if N(2)=n=0.5? oh shit. No, never mind. I don’t want to think down that ∞ rabbit hole.
Different approach? Yes? From 0=1? Lets reframe it. shall we break 0/1 or 1/0 and show they both work in reciprocation? 2^n again to be villain. (2^0)/(2^1)=0/1 if and where (2^1)/(2^0)=1/0 meaning 0/1=1/2 if 1/0=2 allowing 0/1^-n=1/0^n and 1/0^-n=0/1^n.
okay. That went south. Still broken in the mainstream view. 
lets try something different, if 2n is two lines is -1->1 with no zero, what is the zero point line? Well, its 2n=1 where n=0.5, done in radius to -0.5->0.5 meaning 1 is actually 0.5->1.5 if 2 is 1.5->2.5 meaning 2n+1 equivalent to 2n is N to n equivalency, but 2n=2n+1. 
-0.5->0.5 is 1, 2n n=0.5
-1.5->1.5 is 3, 2n n=1.5
-2.5->2.5 is 5, 2n n=2.5
wait, aren’t odds under 2n+1 rule?
I got lost. What was we doing again? Oh right the meta math joke. I mean its not like we can map 2^n×2^-n=1 to thermal timescales for physical quantization. None of this means anything. 😊 I mean hot is positive to cold’s negative and all, but I digress. It all means nothing. Which means it’s telling everything is static state of motion. Never still. 
Oh, the joke is on us. The universe is the one telling it. 
the punchline is how we think we understand, when truly, we do not. We forgot what we once knew, and replaced it with law, that we think of and treat as a higher power than the reality that inspired it. 
Maybe the degrees of separation are something that we did to ourselves, from our native and naïve, but open, origin point.
You see, 2^(n-n) sets vacuum scale as always present and there. Perfect vacuum is unachievable. When we realize this with Einstein’s work, we realize that the issue is the workaround to solve for mass quantization we cannot see. Photonic mass. I fear its at the tip of boundary of observability, set as mc^2 or E in scale of quantum foam. If m sets observable scale to a normalized threshold, it becomes 1. 1^x=1. Meaning its subjective scale does not change, even though its intrinsic value does. Although, when we isolate 1=2((1/(√2))^2) we can see the 1/√2 gate, giving it a gate area of ((1/(√2))^3)=0.353553390593 where 2(1/√2^3) ≊1/√2 if 2((2(1/√2^3))^2)=1

want to see the rabbit hole?
its x=2((2(x/√2^3))^2)
duality by lines: 1.5sin(x): [(0,0), (π,0), (2π,0)]
Tertiary by lines: A: Sin(1.5x): [(0,0), (2π/3,0), (4π/3,0), (2π,0)]
  B: 3sin(2x): [(0,0), (π/2,0), (π,0), (3 π/2,0), (2 π,0)]
Hexarity by lines: 2 sin(x): [(0,0), (π/3,0), (2 π/3,0), (π,0), (4π/3,0), (5 π /3,0), (2 π,0)]
meaning:
a(sin)(bx) where a=b is conserved. 
a(sin)(bx) where a<b if a is static in comparison shows nuance of depth perception or smaller movement scale on similar sized spheres to our conserved version
a(sin)(bx) where a>b if b is static in comparison shows faster spin perception or smaller movement scale leading to a bigger perception, when on similar sized spheres to our conserved version.