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Openai/693c0f4f-255c-8008-92e9-0cd44c6d6226
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==== They rewrite Eq. (4.1) as an optimization problem: ==== z\''=argminz ∥x−f^(z)∥2(4.3)z^\'' = \arg\min_z \; \big\|x - \hat f(z)\big\|^2 \tag{4.3}z\*=argzminx−f^(z)2(4.3) So, for a given (possibly OOD) image xxx: # Define the reconstruction loss: L(z)=∥x−f^(z)∥2.L(z) = \big\|x - \hat f(z)\big\|^2.L(z)=x−f^(z)2. # Start from some initial guess z(0)z^{(0)}z(0). # Do gradient descent: z(t+1)=z(t)−η ∇zL(z(t)).z^{(t+1)} = z^{(t)} - \eta \,\nabla_z L(z^{(t)}).z(t+1)=z(t)−η∇zL(z(t)). Because f^\hat ff^ is differentiable, you can compute ∇zL\nabla_z L∇zL via backprop. The efficiency depends heavily on initialization: * If you start from a random z(0)z^{(0)}z(0), you may need many steps or get stuck. * Their trick: use the encoder as a “System 1” guess: z(0)=g^(x).z^{(0)} = \hat g(x).z(0)=g^(x). So the pipeline for Search is: : Intuition: * g^\hat gg^ is trained only on XIDX_{\text{ID}}XID, so on OOD it might be biased or slightly wrong. * But it’s often close to a good solution. * Gradient-based search corrects g^\hat gg^’s mistakes by explicitly enforcing that the decoded image matches xxx under f^\hat ff^. This is what they show in Fig. 4 (left): encoder gives an initial slot decomposition; search refines it to better match xxx. Pros: * In principle, if f^\hat ff^ truly identifies fff, then solving (4.3) correctly recovers the “right” slots for any x∈Xx \in Xx∈X, including OOD. * You don’t need extra training data. Cons: * It’s online and per-image expensive (hundreds of gradient steps in experiments). * For large models / many images, this is slow.
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